document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180645>Question 180645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation secA =x is equivalent to the equation.<BR>\n" );
document.write( "A=cos x<BR>\n" );
document.write( "A=1/cos x<BR>\n" );
document.write( "A=1/sec x<BR>\n" );
document.write( "A= sec^-1x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137140 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If secA =x, then to solve for A you must do the INVERSE operation to both sides in order to \"undo\" the sec.  The inverse operation is called the \"Arccos\" or sometimes it is written \"sec^-1\".  So the answer is \r<BR>\n" );
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document.write( "A = Arcsec x  or A =sec^-1 x\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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