document.write( "Question 182645: jim ran 12 miles in 45 minutes less than it took jon to walk 5 miles. if jim's speed was 5 miles faster than jon's speed, what was jim's speed.\r
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Algebra.Com's Answer #137125 by stanbon(75887)\"\" \"About 
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jim ran 12 miles in 45 minutes less than it took jon to walk 5 miles. if jim's speed was 5 miles faster than jon's speed, what was jim's speed.
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\n" ); document.write( "Jon DATA:
\n" ); document.write( "time = x hrs; distance = 5 miles ; rate = d/t = 5/x mph
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\n" ); document.write( "\n" ); document.write( "Jim DATA:
\n" ); document.write( "distance = 12 miles ; time = x-(3/4) hr; rate = d/t = 12/(x-(3/4))
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\n" ); document.write( "Equation:
\n" ); document.write( "jim rate = jon rate + 5
\n" ); document.write( "12/(x-(3/4)) = (5/x) + 5\r
\n" ); document.write( "\n" ); document.write( "48/(4x-3) = (5 + 5x)/x\r
\n" ); document.write( "\n" ); document.write( "48x = 5(x+1)(4x-3)
\n" ); document.write( "48x = 5[4x^2 +x - 3]
\n" ); document.write( "20x^2 - 43x - 15 = 0
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\n" ); document.write( "x = [43 +- sqrt(43^2 - 4*20*-15)]/40\r
\n" ); document.write( "\n" ); document.write( "x = [43 + 55.22]/40
\n" ); document.write( "x = 2.455 mph
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\n" ); document.write( "Jim's rate = d/t = 12/(x-(3/4))
\n" ); document.write( "Jim's rate = 12/(2.455-0.75) = 7.038 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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