document.write( "Question 182645: jim ran 12 miles in 45 minutes less than it took jon to walk 5 miles. if jim's speed was 5 miles faster than jon's speed, what was jim's speed.\r
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document.write( "i need help ASAP, please and thank you!! \n" );
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Algebra.Com's Answer #137125 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! jim ran 12 miles in 45 minutes less than it took jon to walk 5 miles. if jim's speed was 5 miles faster than jon's speed, what was jim's speed. \n" ); document.write( "------------------------ \n" ); document.write( "Jon DATA: \n" ); document.write( "time = x hrs; distance = 5 miles ; rate = d/t = 5/x mph \n" ); document.write( "-----------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "Jim DATA: \n" ); document.write( "distance = 12 miles ; time = x-(3/4) hr; rate = d/t = 12/(x-(3/4)) \n" ); document.write( "---------------------------------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "jim rate = jon rate + 5 \n" ); document.write( "12/(x-(3/4)) = (5/x) + 5\r \n" ); document.write( "\n" ); document.write( "48/(4x-3) = (5 + 5x)/x\r \n" ); document.write( "\n" ); document.write( "48x = 5(x+1)(4x-3) \n" ); document.write( "48x = 5[4x^2 +x - 3] \n" ); document.write( "20x^2 - 43x - 15 = 0 \n" ); document.write( "--- \n" ); document.write( "x = [43 +- sqrt(43^2 - 4*20*-15)]/40\r \n" ); document.write( "\n" ); document.write( "x = [43 + 55.22]/40 \n" ); document.write( "x = 2.455 mph \n" ); document.write( "------------------ \n" ); document.write( "Jim's rate = d/t = 12/(x-(3/4)) \n" ); document.write( "Jim's rate = 12/(2.455-0.75) = 7.038 mph \n" ); document.write( "========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |