document.write( "Question 182580: A cabin cruiser travels 20 miles in the same time that a power boat travels 40 miles. The cruiser travels 5 mph slower than the power boat. Find the speed of each boat. \n" ); document.write( "

Algebra.Com's Answer #137072 by josmiceli(19441) $\"\"$ $\"About$

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For both boats, the time travelling is the same
\n" ); document.write( "For cabin cruiser:
\n" ); document.write( "(1) $\"d%5B1%5D+=+r%5B1%5D%2At\"$
\n" ); document.write( "For power boat:
\n" ); document.write( "(2) $\"d%5B2%5D+=+r%5B2%5D%2At\"$
\n" ); document.write( "given:
\n" ); document.write( " $\"d%5B1%5D+=+20\"$
\n" ); document.write( " $\"d%5B2%5D+=+40\"$
\n" ); document.write( " $\"r%5B1%5D+=+r%5B2%5D+-+5\"$
\n" ); document.write( "Rewriting (1) and (2):
\n" ); document.write( "(1) $\"20+=+%28r%5B2%5D+-+5%29%2At\"$
\n" ); document.write( "(2) $\"40+=+r%5B2%5D%2At\"$
\n" ); document.write( "This is 2 equations and 2 unknowns, so it's solvable
\n" ); document.write( "(1) $\"20+=+r%5B2%5D%2At+-+5t\"$
\n" ); document.write( "(2) $\"40+=+r%5B2%5D%2At\"$
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) $\"40+=+r%5B2%5D%2At\"$
\n" ); document.write( "(1) $\"-20+=+-r%5B2%5D%2At+%2B+5t\"$
\n" ); document.write( " $\"20+=+5t\"$
\n" ); document.write( " $\"t+=+4\"$ hrs
\n" ); document.write( "------------------
\n" ); document.write( "(1) $\"20+=+r%5B1%5D%2At\"$
\n" ); document.write( "(1) $\"20+=+r%5B1%5D%2A4\"$
\n" ); document.write( " $\"r%5B1%5D+=+5\"$ mi/hr
\n" ); document.write( "--------------------
\n" ); document.write( "(2) $\"40+=+r%5B2%5D%2At\"$
\n" ); document.write( "(2) $\"40+=+r%5B2%5D%2A4\"$
\n" ); document.write( " $\"r%5B2%5D+=+10\"$ mi/hr
\n" ); document.write( "--------------------
\n" ); document.write( "The cabin cruiser goes 5 mi/hr and
\n" ); document.write( "the power boat goes 10 mi/hr \n" ); document.write( "

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