document.write( "Question 182559: A merchant blends tea that sells for $2.85lb with tea that sells for $2.60lb to produce a 90lb mixture that sells for $2.75lb. How many pounds of each type of tea does the merchabt use in the blend? \n" ); document.write( "
Algebra.Com's Answer #137057 by ankor@dixie-net.com(22740)\"\" \"About 
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A merchant blends tea that sells for $2.85 lb with tea that sells for $2.60 lb
\n" ); document.write( "to produce a 90 lb mixture that sells for $2.75 lab. How many pounds of each
\n" ); document.write( "type of tea does the merchant use in the blend?
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\n" ); document.write( "Let x = amt of $2.85 lb tea
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\n" ); document.write( "It says the resulting amt will be 90 lb, therefore:
\n" ); document.write( "(90-x) = amt of $2.60 lb tea
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\n" ); document.write( "2.85x + 2.60(90-x) = 2.75(90)
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\n" ); document.write( "2.85x + 234 - 2.6x = 247.5
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\n" ); document.write( "2.85x - 2.60x = 247.5 - 234
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\n" ); document.write( ".25x = 13.5
\n" ); document.write( "x = \"13.5%2F.25\"
\n" ); document.write( "x = 54 lb of $2.85 lb tea required
\n" ); document.write( "then
\n" ); document.write( "90 - 54 = 36 lb of $2.60 lb required
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\n" ); document.write( "Check solution;
\n" ); document.write( "2.85(54) + 2.6(36) = 2.75(90)
\n" ); document.write( "153.9 + 93.6 = 247.5 \n" ); document.write( "
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