document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182559>Question 182559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant blends tea that sells for $2.85lb with tea that sells for $2.60lb to produce a 90lb mixture that sells for $2.75lb.  How many pounds of each type of tea does the merchabt use in the blend? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137056 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2.85X+2.60(90-X)=2.75*90<BR>\n" );
document.write( "2.85X+234-2.60X=247.5<BR>\n" );
document.write( ".25X=247.5-234<BR>\n" );
document.write( ".25X=13.5<BR>\n" );
document.write( "X=13.5/.25<BR>\n" );
document.write( "X=54 LB. OF $2.85 TEA.<BR>\n" );
document.write( "90-54=36 LB. OF $2.60 TEA.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2.85*54+2.60*36=2.75*90<BR>\n" );
document.write( "153.9+93.6=247.5<BR>\n" );
document.write( "247.5=247.5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );