document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25578>Question 25578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a badminton court is 128 feet. After a game of badminton, a player’s coach estimates that the athlete has run a total of 444 feet, which is equivalent to 6 times the court’s length plus nine times its width. What are the dimensions of the badminton court?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13704 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is 2l+2w=128<BR>\n" );
document.write( "In addition you are told the following:<BR>\n" );
document.write( " 6l+9w=444\r<BR>\n" );
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document.write( "Solve by substitution:<BR>\n" );
document.write( "l+w=64<BR>\n" );
document.write( "l=64-w<BR>\n" );
document.write( "Rewrite the 2nd equation to get:<BR>\n" );
document.write( "6(64-w)+9w=444<BR>\n" );
document.write( "384-6w+9w=444<BR>\n" );
document.write( "      3w=60<BR>\n" );
document.write( "       w=20 feet<BR>\n" );
document.write( "       l=64-20=44 feet\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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