document.write( "Question 182499This question is from textbook
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document.write( ": One integer is twice another, and their sum is 96. Find the integers. \n" );
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Algebra.Com's Answer #137038 by eperette(173) ![]() You can put this solution on YOUR website! Let \n" ); document.write( "x = integer 1 \n" ); document.write( "y = integer 2\r \n" ); document.write( "\n" ); document.write( "x = 2y \n" ); document.write( "x + y = 96 \n" ); document.write( "we will use substitution to solve this \n" ); document.write( "x + y = 96 \n" ); document.write( "2y + y = 96 \n" ); document.write( "3y = 96 \n" ); document.write( "3y/3 = 96/3 \n" ); document.write( "1y = 32\r \n" ); document.write( "\n" ); document.write( "now lets go back and substitute y=32 to find x \n" ); document.write( "x = 2y \n" ); document.write( "x = 2(32) \n" ); document.write( "y = 64 \n" ); document.write( "answer: smaller number = 32 and larger number = 64 \n" ); document.write( "check: 32+64=96 correct \n" ); document.write( "2(32)=64 correct \n" ); document.write( " \n" ); document.write( " |