document.write( "Question 182499This question is from textbook
\n" ); document.write( ": One integer is twice another, and their sum is 96. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #137038 by eperette(173)\"\" \"About 
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Let
\n" ); document.write( "x = integer 1
\n" ); document.write( "y = integer 2\r
\n" ); document.write( "\n" ); document.write( "x = 2y
\n" ); document.write( "x + y = 96
\n" ); document.write( "we will use substitution to solve this
\n" ); document.write( "x + y = 96
\n" ); document.write( "2y + y = 96
\n" ); document.write( "3y = 96
\n" ); document.write( "3y/3 = 96/3
\n" ); document.write( "1y = 32\r
\n" ); document.write( "\n" ); document.write( "now lets go back and substitute y=32 to find x
\n" ); document.write( "x = 2y
\n" ); document.write( "x = 2(32)
\n" ); document.write( "y = 64
\n" ); document.write( "answer: smaller number = 32 and larger number = 64
\n" ); document.write( "check: 32+64=96 correct
\n" ); document.write( "2(32)=64 correct
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