document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182547>Question 182547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2.\r<BR>\n" );
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document.write( "How are addition and multiplication used to solve a linear equation? Demonstrate by solving \"15x + 7 = 31 + 3x\" \r<BR>\n" );
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document.write( "thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #137022 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=137022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How are addition and multiplication used to solve a linear equation? Demonstrate by solving<BR>\n" );
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document.write( "\"15x + 7 = 31 + 3x\" \r<BR>\n" );
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document.write( "Add 15x to both sides to get:<BR>\n" );
document.write( "7 = 31 + 18x\r<BR>\n" );
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document.write( "Subtract 31 from both sides to get:<BR>\n" );
document.write( "-24 = 18x\r<BR>\n" );
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document.write( "Divide both sides by 18 to get:<BR>\n" );
document.write( "x = -24/18\r<BR>\n" );
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document.write( "Simplify:<BR>\n" );
document.write( "x = -4/3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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