document.write( "Question 296: In a series of spring training games, the Yankees scored 35 runs. The Dodgers and Tigers, respectivly, tallied half and a third as many as the Reds. The Reds' scores were as much below the Yankees' as the Dodgers' were the Tigers'. How many runs did each team score \n" ); document.write( "
Algebra.Com's Answer #137 by arden42(16)\"\" \"About 
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First, we'll put down what we already know:\r
\n" ); document.write( "\n" ); document.write( "\"Y+=+35\"
\n" ); document.write( "\"D+=+R%2F2\"
\n" ); document.write( "\"T+=+R%2F3\"
\n" ); document.write( "\"Y+-+R+=+T+-+D\"\r
\n" ); document.write( "\n" ); document.write( "Since we know Y already, and we can express both D and T in terms of R, lets rewrite the final equation above as:\r
\n" ); document.write( "\n" ); document.write( "\"35+-+R+=+R%2F3+-+R%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Now we have an equation completely in terms of R, so we can work out R. Multiplying by 6 to eliminate fractions (makes it nicer to work with) gives us:\r
\n" ); document.write( "\n" ); document.write( "\"210+-+6R+=+2R+-+3R\"\r
\n" ); document.write( "\n" ); document.write( "Rearranging to get all the R's on one side makes it:\r
\n" ); document.write( "\n" ); document.write( "\"210+=+5R\"\r
\n" ); document.write( "\n" ); document.write( "Divide by 5:\r
\n" ); document.write( "\n" ); document.write( "\"R+=+42\"\r
\n" ); document.write( "\n" ); document.write( "Since D = R/2, and R = 42:\r
\n" ); document.write( "\n" ); document.write( "\"D+=+21\"\r
\n" ); document.write( "\n" ); document.write( "Since T = R/3, and R = 42:\r
\n" ); document.write( "\n" ); document.write( "\"T+=+14\"\r
\n" ); document.write( "\n" ); document.write( "So the final results are:\r
\n" ); document.write( "\n" ); document.write( "The Reds scored 42, the Yankees scored 35, the Dodgers scored 21 and the Tigers scored 14.
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