document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182367>Question 182367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lot has the shape of a right triangle with one leg 2m longer than the other.<BR>\n" );
document.write( "The hypotenuse is 2m less than twice the length of the shorter leg. Find the length of the shorter leg. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136997 by </B><A HREF=/tutors/aboutme.mpl?userid=tvandenberg><B>tvandenberg(45)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tvandenberg><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+a+%2B+2 ALIGN=MIDDLE  ALT=\"b+=+a+%2B+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+sqrt%28a%5E2%2Bb%5E2%29+=+2a+-+2 ALIGN=MIDDLE  ALT=\"c+=+sqrt%28a%5E2%2Bb%5E2%29+=+2a+-+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28a%5E2%2B%28a%2B2%29%5E2%29+=+sqrt%28a%5E2%2Ba%5E2%2B4a%2B4%29+=+sqrt%282a%5E2%2B4a%2B4%29+=+2a-2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2a%5E2%2B4a%2B4+=+%282a-2%29%5E2+=+4a%5E2-4a%2B4 ALIGN=MIDDLE  ALT=\"2a%5E2%2B4a%2B4+=+%282a-2%29%5E2+=+4a%5E2-4a%2B4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2B2a%2B2+=+2a%5E2-2a%2B2 ALIGN=MIDDLE  ALT=\"a%5E2%2B2a%2B2+=+2a%5E2-2a%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-a%5E2%2B4a=0 ALIGN=MIDDLE  ALT=\"-a%5E2%2B4a=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%28-a%2B4%29=0 ALIGN=MIDDLE  ALT=\"a%28-a%2B4%29=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = 0 or 4<BR>\n" );
document.write( "--<BR>\n" );
document.write( "Since a triangle can't have a side of 0, a = 4<BR>\n" );
document.write( "Not needed, but b = 6, c = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2852%29+=+2%2Asqrt%2813%29 ALIGN=MIDDLE  ALT=\"sqrt%2852%29+=+2%2Asqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );