document.write( "Question 182379This question is from textbook aLGEBRA A COMBINED APPROACH
\n" ); document.write( ": 45 INCH BOARD IS TO BE CUT INTO THREE PIECES SO THAT THE SECOND PIECE IS 3 TIMES AS LONG AS THE FIRST PIECE AND THE THIRD PIECE IS 5 TIMES AS LONG AS THE FIRST PIECE. IF X REPRESENTS THE LENGTH OF THE FIRST PIECE, FIND THE LENGTHS OF ALL THREE PIECES \n" ); document.write( "
Algebra.Com's Answer #136988 by MathGuyJoe(20)\"\" \"About 
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\n" ); document.write( "Let x = length of 1st piece
\n" ); document.write( "Let y = length of 2nd piece
\n" ); document.write( "Let z = length of 3rd piece
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\n" ); document.write( "We know the total length of the board is 45, so:
\n" ); document.write( "Equation 1: \"+x+%2B+y+%2B+z+=+45+\"
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\n" ); document.write( "We also know that the 2nd piece is 3 times the length of the 1st piece:
\n" ); document.write( "Equation 2: \"+y+=+3x+\"
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\n" ); document.write( "We also know that he 3rd piece is 5 times the length of the 1st piece:
\n" ); document.write( "Equation 3: \"+z+=+5x+\"
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\n" ); document.write( "Now we can substitute the values from equations 2 and 3 into equation 1:
\n" ); document.write( "Equation 1: \"+x+%2B+y+%2B+z+=+45+\"
\n" ); document.write( "Substitute: \"+x+%2B+%283x%29+%2B+%285x%29+=+45+\"\r
\n" ); document.write( "\n" ); document.write( "Solving for x gives us:
\n" ); document.write( "\"+9x+=+45+\"
\n" ); document.write( "\"++x+=+5+\"
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\n" ); document.write( "Substituting this value back into equations 2 and 3 will give us the values of y and z:
\n" ); document.write( "Equation 2: \"+y+=+3x+\"
\n" ); document.write( "Substitute: \"+y+=+3%285%29+\"
\n" ); document.write( "\"+y+=+15+\"
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\n" ); document.write( "Equation 3: \"+z+=+5x+\"
\n" ); document.write( "Substitute: \"+z+=+5%285%29+\"
\n" ); document.write( "\"+z+=+25+\"
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\n" ); document.write( "So the final answers are x = 5, y = 15 and z = 25.
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