document.write( "Question 182365This question is from textbook
\n" ); document.write( ": The product of two consecutive integers is 4 less than four times their sum. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #136987 by mastermath(14)\"\" \"About 
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Let the consecutive numbers be n and (n+1) respectively.
\n" ); document.write( "Their sum is (n + n + 1) = (2n + 1)
\n" ); document.write( "Four times their sum = 4(2n + 1)
\n" ); document.write( "The product of the numbers = n(n + 1)
\n" ); document.write( "The product of two consecutive integers is 4 less than four times their sum.
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\n" ); document.write( "So, the equation becomes
\n" ); document.write( "n(n + 1) = 4 (2n + 1) - 4
\n" ); document.write( "n^2 + n = 8n + 4 - 4
\n" ); document.write( "n^2 + n = 8n
\n" ); document.write( "Subtract 8n on both the sides
\n" ); document.write( "n^2 + n - 8n = 8n - 8n
\n" ); document.write( "n^2 - 7n = 0
\n" ); document.write( "n (n - 7) = 0
\n" ); document.write( "Use the zero product rule
\n" ); document.write( "n=0 or (n-7)=0
\n" ); document.write( "n=0 or n=7.
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\n" ); document.write( "If n=0, n+1 = 0 + 1 = 1.
\n" ); document.write( "So, one pair of consecutive integers is 0 and 1.
\n" ); document.write( "If n=7, n+1 = 7 + 1 = 8.
\n" ); document.write( "So, second pair of consecutive integers is 7 and 8.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Mastermath.
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