document.write( "Question 182365This question is from textbook
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document.write( ": The product of two consecutive integers is 4 less than four times their sum. Find the integers. \n" );
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Algebra.Com's Answer #136987 by mastermath(14) ![]() You can put this solution on YOUR website! Let the consecutive numbers be n and (n+1) respectively. \n" ); document.write( "Their sum is (n + n + 1) = (2n + 1) \n" ); document.write( "Four times their sum = 4(2n + 1) \n" ); document.write( "The product of the numbers = n(n + 1) \n" ); document.write( "The product of two consecutive integers is 4 less than four times their sum. \n" ); document.write( "---------------------------------------------------------------------------- \n" ); document.write( "So, the equation becomes \n" ); document.write( "n(n + 1) = 4 (2n + 1) - 4 \n" ); document.write( "n^2 + n = 8n + 4 - 4 \n" ); document.write( "n^2 + n = 8n \n" ); document.write( "Subtract 8n on both the sides \n" ); document.write( "n^2 + n - 8n = 8n - 8n \n" ); document.write( "n^2 - 7n = 0 \n" ); document.write( "n (n - 7) = 0 \n" ); document.write( "Use the zero product rule \n" ); document.write( "n=0 or (n-7)=0 \n" ); document.write( "n=0 or n=7. \n" ); document.write( "---------------------------------------------------- \n" ); document.write( "If n=0, n+1 = 0 + 1 = 1. \n" ); document.write( "So, one pair of consecutive integers is 0 and 1. \n" ); document.write( "If n=7, n+1 = 7 + 1 = 8. \n" ); document.write( "So, second pair of consecutive integers is 7 and 8. \n" ); document.write( "----------------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Mastermath. \n" ); document.write( " \n" ); document.write( " |