document.write( "Question 182386: Triangle ABC with a vertices A(0,square root of 27) B(3,o) C(-3,0)
\n" ); document.write( "Use the distance formula to classify the triangle by its sides.
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Algebra.Com's Answer #136986 by tvandenberg(45)\"\" \"About 
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Assuming by B(3,o) you meant (3,0)...\r
\n" ); document.write( "\n" ); document.write( "Distance is from \"a%5E2%2Bb%5E2=c%5E2\" or \"c+=+sqrt%28a%5E2%2Bb%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "But, that means you need to know the a and the b. If you plotted this triangle, you'd see that AB = AC, as A is centered on the x-axis between B and C, and B and C are at the same y-value.\r
\n" ); document.write( "\n" ); document.write( "So, let's start with the easy one, BC = 6, since it is from -3 to 3.\r
\n" ); document.write( "\n" ); document.write( "So, you can either do AB or AC, I chose AB, for no real reason.\r
\n" ); document.write( "\n" ); document.write( "So, a and b, from the equation above are the x distance and y distance.\r
\n" ); document.write( "\n" ); document.write( "So, x-distance is (3-0) = 3
\n" ); document.write( "y-distance = \"sqrt%2827%29-0\" = \"sqrt%2827%29\"\r
\n" ); document.write( "\n" ); document.write( "\"c+=+sqrt%28a%5E2%2Bb%5E2%29+=+sqrt%283%5E2%2B%28sqrt%2827%29%29%5E2%29+=+sqrt%2836%29+=+6\"\r
\n" ); document.write( "\n" ); document.write( "So the side are 6,6,6 which is an equilateral triangle.
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