document.write( "Question 182456: y=-2x-3
\n" ); document.write( "6x-8y=-20 \n" ); document.write( "
Algebra.Com's Answer #136965 by MathGuyJoe(20)\"\" \"About 
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You can solve this system using substitution. Since one of the equations is already solved for y:
\n" ); document.write( "y = -2x - 3
\n" ); document.write( "

\n" ); document.write( "We can substitute it directly into the second equation:
\n" ); document.write( "6x - 8y = -20
\n" ); document.write( "Subsitute (-2x -3) for 'y':
\n" ); document.write( "6x - 8(-2x - 3) = -20
\n" ); document.write( "Distribute the -8 through (-2x - 3):
\n" ); document.write( "6x + 16x + 24 = -20
\n" ); document.write( "Simplify:
\n" ); document.write( "22x + 24 = -20
\n" ); document.write( "Subtract 24 from both sides:
\n" ); document.write( "22x + 24 (- 24) = -20 (- 24)
\n" ); document.write( "22x = -44
\n" ); document.write( "Divide both sides by 22:
\n" ); document.write( "22x (/ 22) = -44 (/ 22)
\n" ); document.write( "x = -2
\n" ); document.write( "

\n" ); document.write( "Now that we know x = -2, we can substitute back into either equation above to find y:
\n" ); document.write( "y = -2x - 3
\n" ); document.write( "y = -2(-2) - 3
\n" ); document.write( "y = 4 - 3
\n" ); document.write( "y = 1
\n" ); document.write( "

\n" ); document.write( "So our answers are x = -2 and y = 1. \n" ); document.write( "
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