document.write( "Question 182478: Factor completely: 4x^2y - 8xy I am having trouble with the factoring of this and of 2x^2 -22x + 60 How do I get the - 22 factored in? Thanks for your help!
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Algebra.Com's Answer #136948 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2y-8xy\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"4xy%28x-2%29\" Factor out the GCF \"4xy\"\r
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\n" ); document.write( "\n" ); document.write( "So \"4x%5E2y-8xy\" factors to \"4xy%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-22x%2B60\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2-11x%2B30%29\" Factor out the GCF \"2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"x%5E2-11x%2B30\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2-11x%2B30\", we can see that the first coefficient is \"1\", the second coefficient is \"-11\", and the last term is \"30\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"30\" to get \"%281%29%2830%29=30\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"30\" (the previous product) and add to the second coefficient \"-11\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"30\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"30\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,5,6,10,15,30\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-5,-6,-10,-15,-30\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"30\".\r
\n" ); document.write( "\n" ); document.write( "1*30
\n" ); document.write( "2*15
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\n" ); document.write( "(-1)*(-30)
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-11\":\r
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First NumberSecond NumberSum
1301+30=31
2152+15=17
3103+10=13
565+6=11
-1-30-1+(-30)=-31
-2-15-2+(-15)=-17
-3-10-3+(-10)=-13
-5-6-5+(-6)=-11
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-5\" and \"-6\" add to \"-11\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-5\" and \"-6\" both multiply to \"30\" and add to \"-11\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-11x\" with \"-5x-6x\". Remember, \"-5\" and \"-6\" add to \"-11\". So this shows us that \"-5x-6x=-11x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%28-5x-6x%29%2B30\" Replace the second term \"-11x\" with \"-5x-6x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-5x%29%2B%28-6x%2B30%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-5%29%2B%28-6x%2B30%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-5%29-6%28x-5%29\" Factor out \"6\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-6%29%28x-5%29\" Combine like terms. Or factor out the common term \"x-5\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-11x%2B30\" factors to \"%28x-6%29%28x-5%29\".\r
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\n" ); document.write( "\n" ); document.write( "So our expression goes from \"2%28x%5E2-11x%2B30%29\" and factors further to \"2%28x-6%29%28x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%5E2-22x%2B60\" completely factors to \"2%28x-6%29%28x-5%29\"\r
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