document.write( "Question 182430This question is from textbook prealgebra and introductory algebra
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document.write( ": A motorcycle breaks down and the rider must walk the rest of the way to work. The motorcycle was being driven at 45 mph, and the rider walks at a speed of 6 mph. The distance from home to work is 25 mi, and the total time for the trip was 2 hrs. How far did the motorcycle go before it broke down? \n" );
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Algebra.Com's Answer #136917 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A motorcycle breaks down and the rider must walk the rest of the way to work. The motorcycle was being driven at 45 mph, and the rider walks at a speed of 6 mph. The distance from home to work is 25 mi, and the total time for the trip was 2 hrs. How far did the motorcycle go before it broke down? \n" ); document.write( "--------------------------------------------------------------------- \n" ); document.write( "Walking DATA: \n" ); document.write( "distance = x miles ; rate = 6 mph ; time = x/6 hrs \n" ); document.write( "---------------------------------------------------- \n" ); document.write( "Motocycle DATA: \n" ); document.write( "rate = 45 mph ; distance = (25-x) mi ; time = (25-x)/45 hrs \n" ); document.write( "---------------------------------------------------------- \n" ); document.write( "Equation : \n" ); document.write( "time + time = 2 hrs \n" ); document.write( "x/6 + (25-x)/45 = 2\r \n" ); document.write( "\n" ); document.write( "45x + 6(25-x) = 2*6*45\r \n" ); document.write( "\n" ); document.write( "45x + 150 - 6x = 6*90 \n" ); document.write( "39x = 540 - 150\r \n" ); document.write( "\n" ); document.write( "39x = 390 \n" ); document.write( "x = 10 miles (distance walked) \n" ); document.write( "25-x = 15 miles (distance ridden) \n" ); document.write( "====================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |