document.write( "Question 182368This question is from textbook Developmental Mathematics
\n" ); document.write( ": Volume of a rectangular Chinese box: The volume of this box is 192 cu. units. Find its length and width. \n" ); document.write( "
Algebra.Com's Answer #136881 by Alan3354(69443)\"\" \"About 
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Volume of a rectangular Chinese box: The volume of this box is 192 cu. units. Find its length and width.
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\n" ); document.write( "Not sufficient information.
\n" ); document.write( "192 = 2*4*24
\n" ); document.write( "192 = 4*6*8 and other combinations.
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\n" ); document.write( "Received additional info, the box is 4 by x by (x+2)
\n" ); document.write( "4*x*(x+2) = 192 (that looks familiar, 4 by 6 by 8, but I'll work it out)
\n" ); document.write( "x*(x+2) = 48
\n" ); document.write( "\"x%5E2+%2B+2x+-+48+=+0\"
\n" ); document.write( "(x-6)*(x+8) = 0
\n" ); document.write( "x = 6 (Ignore the -8, too difficult to construct)
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B2x%2B-48+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A1%2A-48=196\".
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\n" ); document.write( " Discriminant d=196 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+196+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%282%29%2Bsqrt%28+196+%29%29%2F2%5C1+=+6\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%282%29-sqrt%28+196+%29%29%2F2%5C1+=+-8\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B2x%2B-48\" can be factored:
\n" ); document.write( " \"1x%5E2%2B2x%2B-48+=+%28x-6%29%2A%28x--8%29\"
\n" ); document.write( " Again, the answer is: 6, -8.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B2%2Ax%2B-48+%29\"

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