document.write( "Question 182307: A computer store sold 300 items last month. The store sold 6 times as many hard drives as they did CD-ROM drives, and half as many floppy drivs as hard drives. Based on this informatin, how many of each item was sold? \n" ); document.write( "
Algebra.Com's Answer #136838 by J2R2R(94)![]() ![]() You can put this solution on YOUR website! A computer store sold 300 items last month.\r \n" ); document.write( "\n" ); document.write( "The store sold 6 times as many hard drives as they did CD-ROM drives and half as many floppy drives as hard drives.\r \n" ); document.write( "\n" ); document.write( "Based on this information, how many of each item was sold?\r \n" ); document.write( "\n" ); document.write( "Number of Hard Drives = A\r \n" ); document.write( "\n" ); document.write( "Number of CD Rom drives = B\r \n" ); document.write( "\n" ); document.write( "Number of Floppy Drives = C\r \n" ); document.write( "\n" ); document.write( "A + B + C = 300\r \n" ); document.write( "\n" ); document.write( "The store sold 6 times as many hard drives as they did CD-ROM drives:\r \n" ); document.write( "\n" ); document.write( "A = 6B\r \n" ); document.write( "\n" ); document.write( "The store sold half as many floppy drives as hard drives:\r \n" ); document.write( "\n" ); document.write( "C = A/2 (= 3B from above)\r \n" ); document.write( "\n" ); document.write( "Writing A + B + C = 180 in terms of B for A and C:\r \n" ); document.write( "\n" ); document.write( "6B + B + 3B = 300\r \n" ); document.write( "\n" ); document.write( "10B = 300\r \n" ); document.write( "\n" ); document.write( "B = 30 CD Rom drives\r \n" ); document.write( "\n" ); document.write( "A = 180 Hard Drives \r \n" ); document.write( "\n" ); document.write( "C = 90 Floppy Drives \n" ); document.write( " |