document.write( "Question 25489: The boat travels 35 km upstream and then back again in 4 h 48min. If the speed of the boat in still water is 15 km/h, what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #13683 by Paul(988)\"\" \"About 
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\n" ); document.write( "48 min --->0.8h
\n" ); document.write( "Speed of the boat with the water = x+15
\n" ); document.write( "Speed of the boat against a water = x-15
\n" ); document.write( "Total distance = 35
\n" ); document.write( "Total time = 4.8h
\n" ); document.write( "\"35%2Fx-15%2B35%2Fx%2B15=4.8\"
\n" ); document.write( "35[(x-15)-(x+15)]=4.8[(x-15)(x+15)]
\n" ); document.write( "35(-30)=4.8(x^2-225)
\n" ); document.write( "-1050=4.8x^2-1080
\n" ); document.write( "4.8x^2-30=0
\n" ); document.write( "4.8x^2=30
\n" ); document.write( "x^2=6.25
\n" ); document.write( "Square root it.
\n" ); document.write( "x=2.5
\n" ); document.write( "Hence the speed of the current is 2.5km/h.
\n" ); document.write( "Paul.
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