document.write( "Question 25489: The boat travels 35 km upstream and then back again in 4 h 48min. If the speed of the boat in still water is 15 km/h, what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #13683 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "48 min --->0.8h \n" ); document.write( "Speed of the boat with the water = x+15 \n" ); document.write( "Speed of the boat against a water = x-15 \n" ); document.write( "Total distance = 35 \n" ); document.write( "Total time = 4.8h \n" ); document.write( " \n" ); document.write( "35[(x-15)-(x+15)]=4.8[(x-15)(x+15)] \n" ); document.write( "35(-30)=4.8(x^2-225) \n" ); document.write( "-1050=4.8x^2-1080 \n" ); document.write( "4.8x^2-30=0 \n" ); document.write( "4.8x^2=30 \n" ); document.write( "x^2=6.25 \n" ); document.write( "Square root it. \n" ); document.write( "x=2.5 \n" ); document.write( "Hence the speed of the current is 2.5km/h. \n" ); document.write( "Paul. \n" ); document.write( " |