document.write( "Question 182295: Betty is 6 years older than Teresa. Three years ago, Betty's age was four times Teresa's age. Find the age of each girl now? \n" ); document.write( "
Algebra.Com's Answer #136821 by HyperBrain(694)![]() ![]() ![]() You can put this solution on YOUR website! let T+6=Betty's present age \n" ); document.write( "T=Theresa's present age.\r \n" ); document.write( "\n" ); document.write( "Three years ago, Betty's age was four times Teresa's age. 3 years ago, betty was (t+6)-3=t+3 years old while Theresa was t-3 years old.\r \n" ); document.write( "\n" ); document.write( "t+3=4(t-3) \n" ); document.write( "t+3=4t-12 \n" ); document.write( "3=3t-12 \n" ); document.write( "15=3t \n" ); document.write( "t=5>>theresa's age\r \n" ); document.write( "\n" ); document.write( "betty's age=t+6=5+6=11\r \n" ); document.write( "\n" ); document.write( "Therefore, Betty is 11 years old while Betty is 11 years old.\r \n" ); document.write( "\n" ); document.write( "pastime blogtime \n" ); document.write( "Power up, \n" ); document.write( "HyperBrain! \n" ); document.write( " |