document.write( "Question 182273This question is from textbook Elementary and Intermediate Algebra
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document.write( ": 6x - 3(y + 7) = 3
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document.write( "10x = y + 7\r
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document.write( "I don't know how to get this started. All I end up with are two different variables and 1 actual number. Please help \n" );
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Algebra.Com's Answer #136808 by Alan3354(69443) You can put this solution on YOUR website! 6x - 3(y + 7) = 3 --> 6x - 3y - 21 = 3 --> 2x - y - 7 = 1 \n" ); document.write( "2x - y = 8 eqn 1 \n" ); document.write( "10x = y + 7 eqn 2 \n" ); document.write( "Solve for y in eqn 2 \n" ); document.write( "y = 10x - 7 \n" ); document.write( "Sub for y into eqn 1 \n" ); document.write( "2x -(10x-7) = 8 \n" ); document.write( "2x-10x+7 = 8 \n" ); document.write( "-8x = 1 \n" ); document.write( "x = -1/8 \n" ); document.write( "------------ \n" ); document.write( "y = 10x-7 \n" ); document.write( "y = -5/4 - 7 \n" ); document.write( "y = -33/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |