document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182264>Question 182264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangular painting is two thirds its length. If the perimeter is 60 inches, then what are the length and width?\r<BR>\n" );
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document.write( "I know that the formula is P= L2 + W2 but I am dyslexic and the fraction in here is throwing me. I would include what I have done so far but it doesn't even make sense to me.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136800 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start with letting x = the quantity at the end of the first sentence, which in this case is the length.  Don't worry about the fraction.  We'll handle that in the easiest possible way LATER on!!  Don't let the problem intimidate you.  It probably isn't as bad as you think it is.\r<BR>\n" );
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document.write( "Now, let x = length.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29x+=+width ALIGN=MIDDLE  ALT=\"%282%2F3%29x+=+width\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "2W + 2L = Perimeter<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A%282%2F3%29%2Ax+%2B+2%2Ax+=+60 ALIGN=MIDDLE  ALT=\"2%2A%282%2F3%29%2Ax+%2B+2%2Ax+=+60\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%2F3+%2B+2x+=+60 ALIGN=MIDDLE  ALT=\"4x%2F3+%2B+2x+=+60\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, if you don't like fractions (and I don't know anyone who really does!), multiply both sides of the equation times 3:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A%284x%2F3%29+%2B+3%2A2x+=+3%2A60+ ALIGN=MIDDLE  ALT=\"3%2A%284x%2F3%29+%2B+3%2A2x+=+3%2A60+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x+%2B+6x=180 ALIGN=MIDDLE  ALT=\"4x+%2B+6x=180\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10x=180 ALIGN=MIDDLE  ALT=\"10x=180\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=18 ALIGN=MIDDLE  ALT=\"x=18\"   DISABLED_style= \"max-width:90%; height:auto;\" > inches = Length\r<BR>\n" );
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document.write( "Now, to find the width, take 2/3 of 18, which is 12 inches.  \r<BR>\n" );
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document.write( "The check is to see if the perimeter is 60 inches.<BR>\n" );
document.write( "2W + 2L = P<BR>\n" );
document.write( "2*12 + 2*18= 60<BR>\n" );
document.write( "24+36= 60   It checks!!!\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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