document.write( "Question 182253: 2x - 5 sqrt x +2 =0 \n" ); document.write( "
Algebra.Com's Answer #136780 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2x - 5 sqrt x + 2 =0 \n" ); document.write( "-------- \n" ); document.write( "2x - 4sqrt(x) - sqrt(x) + 2 = 0\r \n" ); document.write( "\n" ); document.write( "2sqrt(x)[sqrt(x)-2] - [sqrt(x) -2] = 0\r \n" ); document.write( "\n" ); document.write( "[sqrt(x)-2] [2sqrt(x) -1] = 0\r \n" ); document.write( "\n" ); document.write( "sqrt(x) = 2 or 2sqrt(x) = 1\r \n" ); document.write( "\n" ); document.write( "x = 4 or x = 1/4 \n" ); document.write( "------------------------------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------------------------------------ \n" ); document.write( " |