document.write( "Question 182233This question is from textbook Algebra 1
\n" ); document.write( ": Catherine is camping along a river. It takes her 1.5 hours to paddle her canoe 6 miles upstream from her campsite. Catherine turns her canoe around and returns 6 miles downstream to her campsite in exactly 1 hour. What is the rate of the rivers current and the rate of Catherines paddeling in still water? \n" ); document.write( "
Algebra.Com's Answer #136762 by stanbon(75887)\"\" \"About 
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Catherine is camping along a river. It takes her 1.5 hours to paddle her canoe 6 miles upstream from her campsite. Catherine turns her canoe around and returns 6 miles downstream to her campsite in exactly 1 hour. What is the rate of the rivers current and the rate of Catherines paddeling in still water?
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 6 miles: time = 1.5 hours: rate = 6/(3/2) = 4 mph
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance + 6 miles ; time = 1 hr ; rate = 6/1 = 6 mph
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\n" ); document.write( "Equations:
\n" ); document.write( "b - c = 4 mph
\n" ); document.write( "b + c = 6 mph
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\n" ); document.write( "2b = 10
\n" ); document.write( "b = 5 mph (speed of the boat in still water)
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\n" ); document.write( "Substitute to solve for \"c\":
\n" ); document.write( "5 - c = 4
\n" ); document.write( "c = 1 mph (speed of the currect)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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