document.write( "Question 182233This question is from textbook Algebra 1
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document.write( ": Catherine is camping along a river. It takes her 1.5 hours to paddle her canoe 6 miles upstream from her campsite. Catherine turns her canoe around and returns 6 miles downstream to her campsite in exactly 1 hour. What is the rate of the rivers current and the rate of Catherines paddeling in still water? \n" );
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Algebra.Com's Answer #136762 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Catherine is camping along a river. It takes her 1.5 hours to paddle her canoe 6 miles upstream from her campsite. Catherine turns her canoe around and returns 6 miles downstream to her campsite in exactly 1 hour. What is the rate of the rivers current and the rate of Catherines paddeling in still water? \n" ); document.write( "----------- \n" ); document.write( "Upstream DATA: \n" ); document.write( "distance = 6 miles: time = 1.5 hours: rate = 6/(3/2) = 4 mph \n" ); document.write( "--------------------- \n" ); document.write( "Downstream DATA: \n" ); document.write( "distance + 6 miles ; time = 1 hr ; rate = 6/1 = 6 mph \n" ); document.write( "---------------------- \n" ); document.write( "Equations: \n" ); document.write( "b - c = 4 mph \n" ); document.write( "b + c = 6 mph \n" ); document.write( "-------------- \n" ); document.write( "2b = 10 \n" ); document.write( "b = 5 mph (speed of the boat in still water) \n" ); document.write( "--- \n" ); document.write( "Substitute to solve for \"c\": \n" ); document.write( "5 - c = 4 \n" ); document.write( "c = 1 mph (speed of the currect) \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |