document.write( "Question 182189: Speed Distance & Time: Jimmy rides his bike at 15 mph. He has 10 minutes to get there and he lives 3 miles away. Will Jimmy be on times for class? \n" ); document.write( "
Algebra.Com's Answer #136761 by ptaylor(2198) You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r \n" ); document.write( "r=15 \n" ); document.write( "t=10 min or 10/60 hr=1/6 hr \n" ); document.write( "d=15*(1/6)=2 1/2 hr----------------------No! He will not be on time\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |