document.write( "Question 182125: Solve the equation. t2+1=13/6t
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Algebra.Com's Answer #136730 by checkley77(12844)\"\" \"About 
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t2+1=13/6t
\n" ); document.write( "t^2-13t/6+1=0
\n" ); document.write( "Using the quadratic equation t = (-b +- sqrt( b^2-4*a*c ))/(2*a) we get:
\n" ); document.write( "t=(+13/6+-sqrt[-13/6^2-4*1*1])/2*1
\n" ); document.write( "t=(13/6+-sqrt[4.69444-4])/2
\n" ); document.write( "t=(13/6+-sqrt.69444)/2
\n" ); document.write( "t=(2.16667+-.83333)/2
\n" ); document.write( "t=(2.16667+.83333)/2
\n" ); document.write( "t=3/2=1.5 ans.
\n" ); document.write( "t=(2.166667-.83333)/2
\n" ); document.write( "t=1.3333/2
\n" ); document.write( "t=.66667 ans.\r
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