document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182121>Question 182121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve this?  Factor completely.  12x^2 - 10x -8<BR>\n" );
document.write( "I keep getting confused because I'm supposed to find terms that have a product of negative 8 and a sum of negative 10, but all of the answers doesn't factor back out for me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136728 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First of all, we factor the trinomial,  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x%5E2-10x-8 ALIGN=MIDDLE  ALT=\"12x%5E2-10x-8\"   DISABLED_style= \"max-width:90%; height:auto;\" >. \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x%5E2-10x-8+=+2%286x%5E2-5x-4%29 ALIGN=MIDDLE  ALT=\"12x%5E2-10x-8+=+2%286x%5E2-5x-4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. \r<BR>\n" );
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document.write( "We now need to factor the new trinomial  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%5E2-5x-4 ALIGN=MIDDLE  ALT=\"6x%5E2-5x-4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This means that we now have to find factors that have a product of – 24, and a sum of – 5. These factors are – 8 and + 3. Therefore,  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%5E2-5x-4 ALIGN=MIDDLE  ALT=\"6x%5E2-5x-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > now becomes:    <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%5E2-8x%2B3x-4 ALIGN=MIDDLE  ALT=\"6x%5E2-8x%2B3x-4\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Now, factor each binomial, beginning with the 1st <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%5E2-8x ALIGN=MIDDLE  ALT=\"6x%5E2-8x\"   DISABLED_style= \"max-width:90%; height:auto;\" > and then the second (+ 3x – 4). <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%5E2-8x%2B3x-4 ALIGN=MIDDLE  ALT=\"6x%5E2-8x%2B3x-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 2x(3x – 4) + 1(3x - 4).\r<BR>\n" );
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document.write( "Therefore,  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%5E2-5x-4 ALIGN=MIDDLE  ALT=\"6x%5E2-5x-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > =  (2x + 1)(3x – 4), and <BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12x%5E2-10x-8=2%286x%5E2-5x-4%29 ALIGN=MIDDLE  ALT=\"12x%5E2-10x-8=2%286x%5E2-5x-4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  =  2(2x + 1)(3x – 4).<BR>\n" );
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