document.write( "Question 182199: Find the dimensions of a rectangle that has an area 48 m^2 and a diagonal of length 10 m. \n" ); document.write( "
Algebra.Com's Answer #136726 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let x = the length of the rectangle and y = the width of the rectangle. \n" ); document.write( "The area is x*y = 48 sq.m. \n" ); document.write( "The diagonal is 10 m, so \n" ); document.write( "So we have two equations: \n" ); document.write( "1) \n" ); document.write( "2) \n" ); document.write( "2a) \n" ); document.write( "2a) \n" ); document.write( "2a) \n" ); document.write( "2a) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Discard the negative solutions as the lengths of the rectangle sides can only be positive. \n" ); document.write( "So we have: \n" ); document.write( "y = 6 or 8 and x = 8 or 6 \n" ); document.write( "The dimensions of the rectangle would be: \n" ); document.write( "Length = 8m and width = 6m \n" ); document.write( "Please note that while we solved only for y, the x-value is obtained by substituting y = 8 into eqation 1): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |