document.write( "Question 182034: I have puzzled on this one a while - seems like I have two variables and two equations to solve - having touble setting it up...any suggestions appreciated\r
\n" ); document.write( "\n" ); document.write( "A Fed ex truck leaves San Diego to deliver a package to egg ville. One hour out of San Diego on the road it develops mechanical problems. It now slows its speed down to 3/5th of the average speed up to the time of the mechanical trouble. It hobbles along and gets to egg ville 2 hours late. If the mechanical troubles occurred 50 miles beyond where it had, the delay to egg ville would have been reduced by 40 minutes. Find the distance from San Diego to to egg ville.
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Algebra.Com's Answer #136679 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A Fed ex truck leaves San Diego to deliver a package to egg ville. One hour out
\n" ); document.write( " of San Diego on the road it develops mechanical problems. It now slows its
\n" ); document.write( " speed down to 3/5th of the average speed up to the time of the mechanical
\n" ); document.write( "trouble. It hobbles along and gets to egg ville 2 hours late. If the mechanical
\n" ); document.write( " troubles occurred 50 miles beyond where it had, the delay to egg ville would
\n" ); document.write( " have been reduced by 40 minutes. Find the distance from San Diego to to egg ville.
\n" ); document.write( ":
\n" ); document.write( "use .6 for \"3%2F5\"
\n" ); document.write( ":
\n" ); document.write( "Let s = normal average speed
\n" ); document.write( "Let t = normal time for the trip
\n" ); document.write( "Then
\n" ); document.write( "st = distance of the trip
\n" ); document.write( "1s = distance traveled before problem developed (1 hr)
\n" ); document.write( "Then
\n" ); document.write( "(st - 1s) = distance traveled at .6s average speed
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\n" ); document.write( "write a time equation
\n" ); document.write( ":
\n" ); document.write( "1 hr at normal speed + time at slow speed = normal time + 2 hrs
\n" ); document.write( "1 + \"%28%28st-1s%29%29%2F%28.6s%29\" = t + 2
\n" ); document.write( "factor out s
\n" ); document.write( "1 + \"%28s%28t-1%29%29%2F%28.6s%29\" = t + 2
\n" ); document.write( "Cancel s
\n" ); document.write( "1 + \"%28%28t-1%29%29%2F.6\" = t + 2
\n" ); document.write( "multiply equation by .6
\n" ); document.write( ".6 + t - 1 = .6(t+2)
\n" ); document.write( ".6 - 1 + t = .6t + 1.2
\n" ); document.write( "-.4 + t = .6t + 1.2
\n" ); document.write( "t - .6t = 1.2 + .4
\n" ); document.write( ".4t = 1.6
\n" ); document.write( "t = \"1.6%2F.4\"
\n" ); document.write( "t = 4 hrs normal time for the trip
\n" ); document.write( "then
\n" ); document.write( "4s = distance of the trip
\n" ); document.write( "and
\n" ); document.write( "trip with breakdown: 4 + 2 = 6 hrs (1hr at normal speed & 5hrs at .6 speed)
\n" ); document.write( ":
\n" ); document.write( "\"If the mechanical troubles occurred 50 miles beyond where it had, the delay
\n" ); document.write( " to egg ville would have been reduced by 40 minutes. (2/3 hr)
\n" ); document.write( ":
\n" ); document.write( "Distance at slow speed now = 4s - 1s - 50 = (3s-50)
\n" ); document.write( "total Time now: 6 - \"2%2F3\" = 5.33 hrs (40 min earlier)
\n" ); document.write( ":
\n" ); document.write( "Another time equation
\n" ); document.write( "1 + \"50%2Fs\" + \"%283s-50%29%2F%28.6s%29\" = 5.33
\n" ); document.write( "Multiply equation by .6s
\n" ); document.write( ".6s + .6(50) + 3s - 50 = .6s(5.33)
\n" ); document.write( ".6s + 30 + 3s - 50 = 3.2s (got rid of the repeating decimal)
\n" ); document.write( ".6s + 3s - 20 = 3.2s
\n" ); document.write( "3.6s - 3.2s = 20
\n" ); document.write( ".4s = 20
\n" ); document.write( "s = \"20%2F.4\"
\n" ); document.write( "s = 50 mph is normal speed
\n" ); document.write( "and
\n" ); document.write( ".6(50) = 30 mph is breakdown speed
\n" ); document.write( "then
\n" ); document.write( "4 * 50 = 200 mi is the distance, which is what they want
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\n" ); document.write( "Check solution, find the distance using these values:
\n" ); document.write( "1(50) + 5(30) =
\n" ); document.write( "50 + 150 = 200 mi
\n" ); document.write( "and find the time (dist/speed) for the 2nd scenario
\n" ); document.write( "50/50 + 50/50 + 100/30 =
\n" ); document.write( "1 + 1 + 3.33 = 5.33 hrs
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\n" ); document.write( " Hopefully all this made sense, let me know please.\r
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