document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=182066>Question 182066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motel clerk counts his $1 and $10 bills at the end of a day.  He finds that he has a total of 51 bills having a combined monetary value of $213.  Find the number of bills of each denomination that he has.\r<BR>\n" );
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document.write( "The clerk has  ____ ones and ____ tens.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136652 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number of $1 bills = x, so then number of $10 bills is 51-x.<BR>\n" );
document.write( "From the problem description, you can write:<BR>\n" );
document.write( "x($1)+(51-x)($10) = $213 Simplify and solve for x.<BR>\n" );
document.write( "x+510-10x = 213<BR>\n" );
document.write( "-9x+510 = 213 Add 510 to both sides.<BR>\n" );
document.write( "-9x = -297 Divide both sides by -9<BR>\n" );
document.write( "x = 33 and 51-x = 51-33 = 18.<BR>\n" );
document.write( "The motel clerk has 33 $1 bills and 18 $10 bills. </SPAN>\n" );
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