document.write( "Question 182059: I can not figure out the following equation:\r
\n" ); document.write( "\n" ); document.write( "(z+2)^ -2/3 = 3\r
\n" ); document.write( "\n" ); document.write( "solving for z.\r
\n" ); document.write( "\n" ); document.write( "(z+2) raised to the -2/3 power equals 3.
\n" ); document.write( "

Algebra.Com's Answer #136651 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for z:
\n" ); document.write( "\"%28z%2B2%29%5E%28-2%2F3%29+=+3\" Write the left side as a positive exponent:
\n" ); document.write( "\"1%2F%28z%2B2%29%5E%282%2F3%29+=+3\" Multiply both sides by \"z%2B2%29%5E%282%2F3%29\"
\n" ); document.write( "\"1+=+3%28z%2B2%29%5E%282%2F3%29\" Divide both sides by 3.
\n" ); document.write( "\"1%2F3+=+%28z%2B2%29%5E%282%2F3%29\" Now raise both sides to the \"3%2F2\"power.
\n" ); document.write( "\"%281%2F3%29%5E%283%2F2%29+=+%28%28z%2B2%29%5E%282%2F3%29%29%5E%283%2F2%29\" Multiply the exponents on the right side.
\n" ); document.write( "\"1%2F%283%29%5E%283%2F2%29+=+%28z%2B2%29\" Simplify the left side.
\n" ); document.write( "\"1%2F3sqrt%283%29+=+z%2B2\" Finally, subtract 2 from both sides.
\n" ); document.write( "\"z+=+%281%2F3sqrt%283%29%29-2\" and this can also be written as:
\n" ); document.write( "\"highlight%28z+=+%281-6sqrt%283%29%29%2F3sqrt%283%29%29\"
\n" ); document.write( "
\n" );