document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181967>Question 181967</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/061812991x/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I really cannot wrap my brain around word problems!!!! I really appreciate any help I can get so here is my question thank you! <BR>\n" );
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document.write( "      One car left Valdosta averaging 55 mph. and another car left Atlanta averaging 70 mph. They traveled toward each other on interstate 75 Atlanta is north of Valdosta by 300 miles. When did they meet if they both left at noon? How far south of atlanta did they meet??   \r<BR>\n" );
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document.write( "  I need this put into a linear equation and just cant seem to be able to do it! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136602 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136602\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the distance traveled by the car leaving from Atlanta be x<BR>\n" );
document.write( "Then the distance traveled by the car leaving from Valdosta is 300 - x<BR>\n" );
document.write( "Since the cars left at the same time, their time to the “meeting spot” will be the same<BR>\n" );
document.write( "Therefore, time taken by the car leaving from Atlanta to the “meeting spot” equals the time taken by the car leaving from Valdosta to the “meeting spot”<BR>\n" );
document.write( "This means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F70=%28300-x%29%2F55 ALIGN=MIDDLE  ALT=\"x%2F70=%28300-x%29%2F55\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Cross-multiplying, we get: 55x  =  21,000 – 70x<BR>\n" );
document.write( "125x  =  21000<BR>\n" );
document.write( "x   =   168\r<BR>\n" );
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document.write( "Therefore, the distance traveled by the car leaving from Atlanta to Valdosta is 168 miles.\r<BR>\n" );
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document.write( "Therefore, the time it takes each car to meet = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=168%2F70 ALIGN=MIDDLE  ALT=\"168%2F70\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=132%2F55 ALIGN=MIDDLE  ALT=\"132%2F55\"   DISABLED_style= \"max-width:90%; height:auto;\" > These both equal 2.4 hours, or 2 hours, 24 minutes.\r<BR>\n" );
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document.write( "This means that since they both left at 12:00noon, they will meet 2 hours, 24 minutes later, or 2:24pm.\r<BR>\n" );
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document.write( "Since south of Atlanta indicates the car that left from Atlanta (north) to Valdosta (south), then they would meet 168 miles south of Atlanta.<BR>\n" );
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