document.write( "Question 181720: Use Substitution to solve each system of equations. If the system does not have exactly one solution, state whether it has no solution or infinitely many solutions. 1/2x+2y=12 and x-2y=6 \n" ); document.write( "
Algebra.Com's Answer #136551 by ankor@dixie-net.com(22740)\"\" \"About 
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1/2x + 2y = 12 and x - 2y = 6
\n" ); document.write( ":
\n" ); document.write( "Get rid of that annoying denominator, multiply the 1st equation by two
\n" ); document.write( "x + 4y = 24
\n" ); document.write( "Arrange for substitution:
\n" ); document.write( "x = (24 - 4y)
\n" ); document.write( ":
\n" ); document.write( "Substitute this for x in the 2nd equation
\n" ); document.write( "x - 2y = 6
\n" ); document.write( "(24-4y) - 2y = 6
\n" ); document.write( "-4y - 2y = 6 - 24
\n" ); document.write( "-6y = -18
\n" ); document.write( "6y = 18; multiplied both sides by -1
\n" ); document.write( "y = \"18%2F6\"
\n" ); document.write( "y = 3
\n" ); document.write( ":
\n" ); document.write( "Find x using x = 24-4y
\n" ); document.write( "x = 24 - 4(3)
\n" ); document.write( "x = 24 - 12
\n" ); document.write( "x = 12
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the the 1st equation:
\n" ); document.write( "1/2x + 2y = 12
\n" ); document.write( "\"1%2F2\"*12 + 2(3) =
\n" ); document.write( "6 + 6 = 12
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