document.write( "Question 181925: If a ball is thrown into the air with an initial velicity of 52 m/s from a height of 6 m above the ground, its height after t seconds is given by the equation s(t)= -4.9t^2 +52t +6\r
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document.write( "a) what is the time it takes to het to maximum height?
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document.write( "b) what is the maximum height?
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document.write( "c) how long does it take the ball to get to ground level? \n" );
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Algebra.Com's Answer #136547 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! If a ball is thrown into the air with an initial velicity of 52 m/s from a height of 6 m above the ground, its height after t seconds is given by the equation s(t)= -4.9t^2 +52t +6 \n" ); document.write( "a) what is the time it takes to het to maximum height? \n" ); document.write( "that would be the \"axis of symmetry\" found at \n" ); document.write( "t = -b/2a \n" ); document.write( "t = -52/2(-4.9) \n" ); document.write( "t = -52/(-9.8) \n" ); document.write( "t = 5.306 seconds \n" ); document.write( ". \n" ); document.write( "b) what is the maximum height? \n" ); document.write( "Plug the answer above into: \n" ); document.write( "s(t)= -4.9t^2 +52t +6 \n" ); document.write( "s(5.306)= -4.9(5.306)^2 +52(5.306) +6 \n" ); document.write( "s(5.306)= -4.9(28.153636) + (275.912) +6 \n" ); document.write( "s(5.306)= -137.9528164 + 281.912 \n" ); document.write( "s(5.306)= 143.959 feet \n" ); document.write( ". \n" ); document.write( "c) how long does it take the ball to get to ground level? \n" ); document.write( "set s(t) to zero and solve: \n" ); document.write( "s(t)= -4.9t^2 +52t +6 \n" ); document.write( "0= -4.9t^2 +52t +6 \n" ); document.write( "Applying the quadratic equation yields: \n" ); document.write( "t = {-0.114, 10.726} \n" ); document.write( "Toss out the negative solution. \n" ); document.write( "t = 10.726 seconds \n" ); document.write( ". \n" ); document.write( "Below is the details of the quadratic solution: \n" ); document.write( "
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