document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181919>Question 181919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a triangle is 6 cm longer than its altitude. If the area of the triangle is 108 sq. cm, then what is the length of the base? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136539 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The base of a triangle is 6 cm longer than its altitude. If the area of the triangle is 108 sq. cm, then what is the length of the base?<BR>\n" );
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document.write( "Area for any triangle = (1/2)bh<BR>\n" );
document.write( "where<BR>\n" );
document.write( "b is length of base<BR>\n" );
document.write( "h is length of height or altitude<BR>\n" );
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document.write( "Let x = altitude<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x+6 = base<BR>\n" );
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document.write( "108 = (1/2)(x+6)(x)<BR>\n" );
document.write( "216 = (x+6)(x)<BR>\n" );
document.write( "216 = x^2+6x<BR>\n" );
document.write( "0 = x^2+6x-216<BR>\n" );
document.write( "0 = (x-12)(x+18)<BR>\n" );
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document.write( "x = {12, -18}<BR>\n" );
document.write( "Throw out the negative solution leaving<BR>\n" );
document.write( "x = 12 cm (altitude)<BR>\n" );
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document.write( "Base:<BR>\n" );
document.write( "x+6 = 12+6 = 18 cm (length of base) </SPAN>\n" );
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