document.write( "Question 181915: Please help!\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 5 cm, what are the dimensions of the rectangle in centimeters rounded to the nearest tenth?
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Algebra.Com's Answer #136536 by nerdybill(7384)\"\" \"About 
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The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 5 cm, what are the dimensions of the rectangle in centimeters rounded to the nearest tenth?
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\n" ); document.write( "You must apply Pythagorean theorem:
\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w+1 = length
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\n" ); document.write( "Pythagorean theorem:
\n" ); document.write( "w^2 + (w+1)^2 = 5^2
\n" ); document.write( "w^2 + w^2+2w+1 = 25
\n" ); document.write( "2w^2+2w+1 = 25
\n" ); document.write( "2w^2+2w-24 = 0
\n" ); document.write( "w^2+w-12 = 0
\n" ); document.write( "(w-4)(w+3) = 0
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\n" ); document.write( "w = {4,-3}
\n" ); document.write( "Throw out the negative value...
\n" ); document.write( "w = 4.0 cm (width)
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\n" ); document.write( "Length:
\n" ); document.write( "w+1 = 4+1 = 5.0 cm (length)
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