document.write( "Question 181915: Please help!\r
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document.write( "The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 5 cm, what are the dimensions of the rectangle in centimeters rounded to the nearest tenth? \n" );
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Algebra.Com's Answer #136536 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 5 cm, what are the dimensions of the rectangle in centimeters rounded to the nearest tenth? \n" ); document.write( ". \n" ); document.write( "You must apply Pythagorean theorem: \n" ); document.write( "Let w = width \n" ); document.write( "then \n" ); document.write( "w+1 = length \n" ); document.write( ". \n" ); document.write( "Pythagorean theorem: \n" ); document.write( "w^2 + (w+1)^2 = 5^2 \n" ); document.write( "w^2 + w^2+2w+1 = 25 \n" ); document.write( "2w^2+2w+1 = 25 \n" ); document.write( "2w^2+2w-24 = 0 \n" ); document.write( "w^2+w-12 = 0 \n" ); document.write( "(w-4)(w+3) = 0 \n" ); document.write( ". \n" ); document.write( "w = {4,-3} \n" ); document.write( "Throw out the negative value... \n" ); document.write( "w = 4.0 cm (width) \n" ); document.write( ". \n" ); document.write( "Length: \n" ); document.write( "w+1 = 4+1 = 5.0 cm (length) \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |