document.write( "Question 181897: An express train travels 150 km in the same time that a freight train travels 100km. The average speed of the freight train is 20km/h less than that of the express train. Find the speed of each train.
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Algebra.Com's Answer #136530 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An express train travels 150 km in the same time that a freight train travels 100km. The average speed of the freight train is 20km/h less than that of the express train. Find the speed of each train. \n" ); document.write( "----------- \n" ); document.write( "Express DATA: \n" ); document.write( "distance = 150 km ; rate = x km/h ; time = d/r = 150/x hrs. \n" ); document.write( "------------- \n" ); document.write( "Freight DATA: \n" ); document.write( "distance = 100 km; rate = (x-20) km/h ; time = d/r = 100/(x-20) hrs. \n" ); document.write( "------------- \n" ); document.write( "Equation: \n" ); document.write( "time = time \n" ); document.write( "150/x = 100/(x-20) \n" ); document.write( "100x = 150(x-20) \n" ); document.write( "100x = 150x - 3000 \n" ); document.write( "-50x = -3000 \n" ); document.write( "x = 60 km/h (speed of the express train) \n" ); document.write( "------- \n" ); document.write( "x-20 = 40 km/h (speed of the freight train) \n" ); document.write( "============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |