document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181902>Question 181902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cemist has 60 g of solution that is 70 % acid. How much water should be added to make a sloution that is 40% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136525 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A cemist has 60 g of solution that is 70 % acid. How much water should be added to make a sloution that is 40% acid?<BR>\n" );
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document.write( "The starting solution has 42 grams of acid (60*0.7).<BR>\n" );
document.write( "This same 42 grams will be in the solution with more water to make it 40$.<BR>\n" );
document.write( "If 42 grams is 40% of the solution, the total solution will be 105 grams.<BR>\n" );
document.write( "So 45 grams of water must be added.<BR>\n" );
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