document.write( "Question 181883: The line through (2,-3) that is perpendicular to the line y= -4x + 8 written in standard form containing only integer coefficients. I am having a horrible time with these graphs, any help is greatly appreciated! \n" ); document.write( "
Algebra.Com's Answer #136508 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "We can see that the equation \"y=-4%2Ax%2B8\" has a slope \"m=-4\" and a y-intercept \"b=8\".\r
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\n" ); document.write( "\n" ); document.write( "Now to find the slope of the perpendicular line, simply flip the slope \"m=-4\" to get \"m=-1%2F4\". Now change the sign to get \"m=1%2F4\". So the perpendicular slope is \"m=1%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope \"m=-4\" and the coordinates of the given point .\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y--3=%281%2F4%29%28x-2%29\" Plug in \"m=1%2F4\", \"x%5B1%5D=2\", and \"y%5B1%5D=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=%281%2F4%29%28x-2%29\" Rewrite \"y--3\" as \"y%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%28y%2B3%29=x-2\" Multiply both sides by 4.\r
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\n" ); document.write( "\n" ); document.write( "\"4y%2B12=x-2\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"4y=x-2-12\" Subtract 12 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4y-x=-2-12\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4y-x=-14\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-x%2B4y=-14\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x-4y=14\" Multiply EVERY term by -1 to make the \"x\" coefficient positive.\r
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\n" ); document.write( "\n" ); document.write( "Answer: \r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line that is perpendicular to \"y=-4%2Ax%2B8\" and goes through the point (2,-3) in standard form is \"x-4y=14\"\r
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\n" ); document.write( "\n" ); document.write( "Here's the graph of the two lines to verify the answer:\r
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\n" ); document.write( "\n" ); document.write( "Graph of the original equation \"y=-4%2Ax%2B8\" (red) and the perpendicular line \"x-4y=14\" (green) through the point .
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