document.write( "Question 181877: I have tried this but I am having trouble, can you please help. Use substitution to solve each system. If it does not have one solution then put no solution or indinitely many solutions. 4X-5Y=-7 Y=5X \n" ); document.write( "
Algebra.Com's Answer #136491 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"4x-5y=-7\"
\n" ); document.write( "\"y=5x\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x-5%285x%29=-7\" Plug in \"y=5x\" into the first equation. In other words, replace each \"y\" with \"5x\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"4x-25x=-7\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"-21x=-7\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-7%29%2F%28-21%29\" Divide both sides by -21 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"x=1%2F3\", we can plug this into \"y=5x\" to find \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=5%281%2F3%29\" Substitute \"1%2F3\" for each \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=5%2F3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=1%2F3\" and \"y=5%2F3\" which also looks like \r
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