document.write( "Question 181815This question is from textbook Algebra for college students
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document.write( ": Missing numbers. Find two real numbers that have a sum of 6 and a product of 4. \n" );
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Algebra.Com's Answer #136408 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! product of 4---> x*y=4 ---> y=4/x\r \n" ); document.write( "\n" ); document.write( "sum of 6 ----> x+y=6 ---> x+4/x=6 ---> (x^2+4)/x=6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----> x^2-6x+4=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use quadratic formula to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=3+sqrt(5) or x=3-sqrt(5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---> y=4/(3+sqrt(5)) ----> y=3-sqrt(5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---> y=4/(3-sqrt(5)) ----> y=3+sqrt(5)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: Two numbers are 3+sqrt(5) and 3-sqrt(5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |