document.write( "Question 181804: Stella’s Catering is planning a wedding
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document.write( "reception. The bride and groom would like to serve
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document.write( "a nut mixture containing 25% peanuts. Stella has
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document.write( "available mixtures that are either 40% or 10% peanuts.
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document.write( "How much of each type should be mixed to get a 10-lb
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document.write( "mixture that is 25% peanuts?
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Algebra.Com's Answer #136401 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! Stella’s Catering is planning a wedding \n" ); document.write( "reception. The bride and groom would like to serve \n" ); document.write( "a nut mixture containing 25% peanuts. Stella has \n" ); document.write( "available mixtures that are either 40% or 10% peanuts. \n" ); document.write( "How much of each type should be mixed to get a 10-lb \n" ); document.write( "mixture that is 25% peanuts? \n" ); document.write( ": \n" ); document.write( "let x and y be the amount of mixtures of 10% and 40% peanuts respectively \n" ); document.write( ": \n" ); document.write( "x+y=10..............eq 1 \n" ); document.write( ".10x+.4y=.25(10)....eq 2 \n" ); document.write( ": \n" ); document.write( "rewrite eq 1 to \n" ); document.write( ": \n" ); document.write( ".10(10-y)+.4y=2.5 \n" ); document.write( ": \n" ); document.write( "1-.1y+.4y=2.5 \n" ); document.write( ": \n" ); document.write( ".3y=1.5 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " we would expect an equal split since 25% is right in between 10% and 40% \n" ); document.write( " |