document.write( "Question 181778This question is from textbook Algebra
\n" ); document.write( ": the sum of the reciprocals of two consecutive even integers is 11/60. what are the integers? \n" ); document.write( "
Algebra.Com's Answer #136394 by checkley77(12844)\"\" \"About 
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1/x+1/(x+2)=11/60
\n" ); document.write( "(x+2+x)/x(x+2)=11/60
\n" ); document.write( "(2x+2)/(x^2+2x)=11/60
\n" ); document.write( "2x+2=11(x^2+2x)/60
\n" ); document.write( "2x+2=(11x^2+22x)/60
\n" ); document.write( "120x+120=11x^2+22x
\n" ); document.write( "11x^2+22x-120x-120=0
\n" ); document.write( "11x^2-98x-120=0
\n" ); document.write( "Using the quadratic equation x = (-b +- sqrt( b^2-4*a*c ))/(2*a) we get:
\n" ); document.write( "x=(98+-sqrt[-98^2-4*11*-120])/2*11
\n" ); document.write( "x=(98+-sqrt[9604+5280])/22
\n" ); document.write( "x=(98+-sqrt14884)/22
\n" ); document.write( "x=(98+-122)/22
\n" ); document.write( "x=(98+122)/22
\n" ); document.write( "x=220/22
\n" ); document.write( "x=10 ans.
\n" ); document.write( "proof:
\n" ); document.write( "1/10+1/12=11/60
\n" ); document.write( "(12+10)/120=11/60
\n" ); document.write( "22/120=11/60
\n" ); document.write( "11/60=11/60\r
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