document.write( "Question 25353: solve (1/25)^-x=125^x-3. first i did 25^x=125^x-3. then 5^2x=5^3x-3. then 2X=3x-3 and x=3. but the answers supposed to be 9. please help, i have a test tomorow!
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Algebra.Com's Answer #13638 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"%281%2F25%29%5E%28-x%29=125%5E%28x-3%29\"
\n" ); document.write( "\"%2825%29%5Ex+=+125%5E%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now 25 is \"5%5E2\" and 125 is \"5%5E3\", so we have\r
\n" ); document.write( "\n" ); document.write( "\"%285%5E2%29%5Ex+=+%285%5E3%29%5E%28x-3%29\"
\n" ); document.write( "\"5%5E%282x%29+=+5%5E%283%28x-3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "so we have 5 to a power on both sides and it is an equation, so the powers must be the same number, so 2x = 3(x-3)\r
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\n" ); document.write( "\n" ); document.write( "Hence 2x = 3x-9
\n" ); document.write( "--> x = 9\r
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\n" ); document.write( "\n" ); document.write( "jon
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