document.write( "Question 181743: Method of Substitution
\n" ); document.write( "11. Pietro needs to rent a truck for 1 day. He calls two rental companies to compare costs. Joe's Garage charges $80 for the day plus $0.22/km. Ace Trucks charges $100/day and $0.12/km. Under what circcumstances do the two companies charge the same amount? When would it be better for Pietro to rent from Joe's Garage.
\n" ); document.write( "Thank you very much and i need it today please.
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Algebra.Com's Answer #136343 by Mathtut(3670)\"\" \"About 
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Method of Substitution
\n" ); document.write( "11. Pietro needs to rent a truck for 1 day. He calls two rental companies to compare costs. Joe's Garage charges $80 for the day plus $0.22/km. Ace Trucks charges $100/day and $0.12/km. Under what circcumstances do the two companies charge the same amount? When would it be better for Pietro to rent from Joe's Garage.
\n" ); document.write( "Thank you very much and i need it today please.
\n" ); document.write( ":
\n" ); document.write( "1)Joes: C=.22(k)+80.......where C is the cost and k is the km driven
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\n" ); document.write( "Ace: C=.12(k)+100.........where C is the cost and k is the km driven
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\n" ); document.write( "2)for joe to be equal to Ace we just set the equations equal and solve for k
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\n" ); document.write( ".12(k)+100=.22(k)+80
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\n" ); document.write( ".1k=20
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\n" ); document.write( "\"highlight%28k=200%29\"km.......this is the amount of kilometers that makes the costs equal
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\n" ); document.write( "3) now we are looking for Joe < Ace
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\n" ); document.write( "which we write as .22k+80<.12k+100
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\n" ); document.write( ".1k<20
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\n" ); document.write( "\"highlight%28k%3C200%29\"km.....so as long as kilometers stay under 200 Joe will be the cheaper cost. they are equal at 200 and over 200km Ace will be the lower cost
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