document.write( "Question 181705: A cell divides into two identical copies every 4 minutes. How many cells will exist after 5 hours?\r
\n" ); document.write( "\n" ); document.write( "This is where I am at so far:\r
\n" ); document.write( "\n" ); document.write( "60 minutes = 1 hour
\n" ); document.write( "300 minutes = 5 hours
\n" ); document.write( "a cell divides into 2 every 4 minutes
\n" ); document.write( "300/4 = 75
\n" ); document.write( "75^2 = 5625\r
\n" ); document.write( "\n" ); document.write( "I feel that there is something that I missed please look it over and let me know. Thank you
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Algebra.Com's Answer #136317 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A cell divides into two identical copies every 4 minutes. How many cells will exist after 5 hours?
\n" ); document.write( "This is where I am at so far:
\n" ); document.write( "60 minutes = 1 hour
\n" ); document.write( "300 minutes = 5 hours
\n" ); document.write( "a cell divides into 2 every 4 minutes
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\n" ); document.write( "Growth formula:
\n" ); document.write( "A(t) = A(o)(2)^(t/4) where t is number of minutes after t = 0
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\n" ); document.write( "A(300) = 1*2^(300/4)\r
\n" ); document.write( "\n" ); document.write( "A(300) = 2^(75)\r
\n" ); document.write( "\n" ); document.write( "A(300) = 3.77x10^22 cells
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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