document.write( "Question 181480: -6 2/3 x2 + 1 1/3 x = 2/3
\n" ); document.write( "A) x = (-1 +- 10i)/3
\n" ); document.write( "B) x = (-1 +- 3i)/10
\n" ); document.write( "C) x = (1 +- 3i)/-10
\n" ); document.write( "D) x = (-1 +- 3i)/-10
\n" ); document.write( "E) x = (-1 +- 10i)/-3
\n" ); document.write( "F) x = (2 +- 3i)/6\r
\n" ); document.write( "\n" ); document.write( "10. -57 3/5 x2 + 3 3/5 x = -39 3/5 x2 - 7 1/5 x + 14 2/5
\n" ); document.write( "A) x = {2 +- i[SQRT(75)}/10
\n" ); document.write( "B) x = {3 +- i[SQRT(71)]}/-10
\n" ); document.write( "C) x = {-3 +- i[SQRT(57)]}/7
\n" ); document.write( "D) x = {-3 +- i[SQRT(71)]}/-10
\n" ); document.write( "E) x = {-2 +- i[SQRT(75)]}/-7
\n" ); document.write( "F) x = {2 +- i[SQRT(39)]}/14
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Algebra.Com's Answer #136291 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The best approach to both of these is to get rid of the fractional coefficients. For instance,\r
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\n" ); document.write( "\n" ); document.write( "Start by converting the mixed fractions to improper fractions:\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by -3:\r
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\n" ); document.write( "\n" ); document.write( "Add 2 to both sides:\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by \r
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\n" ); document.write( "\n" ); document.write( "Now you have an equivalent equation with integer factors that can be easily solved with the quadratic formula.\r
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\n" ); document.write( "\n" ); document.write( "Follow a similar process for your second problem.\r
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