document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181640>Question 181640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Guy Wire. How long is a guy wire reaching from the top of a 12-ft pole to a point on the ground 8 feet from the pole? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136274 by </B><A HREF=/tutors/aboutme.mpl?userid=Electrified_Levi><B>Electrified_Levi(103)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Electrified_Levi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, Hope I can help,<BR>\n" );
document.write( ".<BR>\n" );
document.write( "First you would draw something sort of like this, you can make it more creative, and draw the actual pole<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+drawing+%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+triangle+%28+-4%2C+-2%2C+4%2C+-2%2C+4%2C+8+%29%2C+locate+++++%28+5%2C4%2C+12%29%2C+locate+%280%2C-3%2C8%29%2C+locate+%280%2C+6%2C+c%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "It will look like a right triangle. <BR>\n" );
document.write( ".<BR>\n" );
document.write( "We are trying to find \"c\", Since we know that it is a right triangle, we can use the Pythagorean Theorem, which will work only with right triangles<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Pythagorean Theorem = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+a%5E2+%2B+b%5E2+=+c%5E2+ ALIGN=MIDDLE  ALT=\"+a%5E2+%2B+b%5E2+=+c%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "\"a\" and \"b\" refer to the legs of the triangle ( the horizontal and vertical lines ). I usually think of \"a\" as the vertical line, and \"b\" with the horizontal line, but it doesn't really matter.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "All you do now is replace the variables with the numbers we know<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+a%5E2+%2B+b%5E2+=+c%5E2+ ALIGN=MIDDLE  ALT=\"+a%5E2+%2B+b%5E2+=+c%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%2812%29%5E2+%2B+%288%29%5E2+=+c%5E2+ ALIGN=MIDDLE  ALT=\"+%2812%29%5E2+%2B+%288%29%5E2+=+c%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%2812%29%2812%29+%2B+%288%29%288%29+=+c%5E2+ ALIGN=MIDDLE  ALT=\"+%2812%29%2812%29+%2B+%288%29%288%29+=+c%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+144+%2B+64+=+c%5E2+ ALIGN=MIDDLE  ALT=\"+144+%2B+64+=+c%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+208+=+c%5E2+ ALIGN=MIDDLE  ALT=\"+208+=+c%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, to find \"c\" we will take the square root of both sides<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+208+=+c%5E2+ ALIGN=MIDDLE  ALT=\"+208+=+c%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sq+rt%28208%29+=+sq+rt%28c%5E2%29+ ALIGN=MIDDLE  ALT=\"+sq+rt%28208%29+=+sq+rt%28c%5E2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt%28+208+%29+=+c+ ALIGN=MIDDLE  ALT=\"+sqrt%28+208+%29+=+c+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+c+=+%2B+sqrt%28208%29++ ALIGN=MIDDLE  ALT=\"+c+=+%2B+sqrt%28208%29++\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+c+=+-+sqrt%28208%29++ ALIGN=MIDDLE  ALT=\"+c+=+-+sqrt%28208%29++\"   DISABLED_style= \"max-width:90%; height:auto;\" >, a measurement cannot be negative so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+c+=+%2B+sqrt%28208%29++ ALIGN=MIDDLE  ALT=\"+c+=+%2B+sqrt%28208%29++\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "If you wanted to be most accurate, you would simplify your answer <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%28208%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%28208%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "You can sometimes simplify radicals if you can find factors of the number that has a whole number as a square root, in this case we can take \"16\" out of \"208\"<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%28208%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%28208%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%2816%29+%28+sqrt+%2813%29%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%2816%29+%28+sqrt+%2813%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16%2813%29=208 ALIGN=MIDDLE  ALT=\"16%2813%29=208\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt+%2816%29+%28+sqrt+%2813%29%29+ ALIGN=MIDDLE  ALT=\"+sqrt+%2816%29+%28+sqrt+%2813%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4+%28sqrt+%2813%29%29+ ALIGN=MIDDLE  ALT=\"+4+%28sqrt+%2813%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, this is the simplified form\r<BR>\n" );
document.write( "\n" );
document.write( ".<BR>\n" );
document.write( "If you rounded your answer, it would be 14.42 ft<BR>\n" );
document.write( ".<BR>\n" );
document.write( "You can round your answer, you need to if they asked you to, but to be the most accurate, you would say the guy wire is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4+%28sqrt%2813%29%29+ ALIGN=MIDDLE  ALT=\"+4+%28sqrt%2813%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > feet long, which would be your answer<BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+drawing+%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+triangle+%28+-4%2C+-2%2C+4%2C+-2%2C+4%2C+8+%29%2C+locate+++++%28+5%2C4%2C+12%29%2C+locate+%280%2C-3%2C8%29%2C+locate+%28-3%2C+6%2C+4+%28sqrt+%2813%29%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "Hope I helped, Levi </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );