document.write( "Question 181548: how can i get resolve this by gaussian elemination with back-substitution or gauss-jordan elimination?\r
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document.write( "3a+b-c=0
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document.write( "2a+3b-5c=1
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document.write( "a-2b+3c=-4 \n" );
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Algebra.Com's Answer #136266 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3a +b -c= 0 \n" ); document.write( "2a+3b-5c= 1 \n" ); document.write( "a-2b+3c= -4 \n" ); document.write( "--------------- \n" ); document.write( "Rearrange the equations: \n" ); document.write( "a-2b+3c =-4 \n" ); document.write( "3a+b-c = 0 \n" ); document.write( "2a+3b-5c= 1 \n" ); document.write( "--------------- \n" ); document.write( "Subtract 3 times the 1st from the 2nd. \n" ); document.write( "Subtract 2times the 1st from the 3rd. \n" ); document.write( "a-2b+3c = -4 \n" ); document.write( "0+7b-10c = 12 \n" ); document.write( "0+7b-11c = 9 \n" ); document.write( "---------------------- \n" ); document.write( "Subtract the 2nd from the 3rd. \n" ); document.write( "a-2b+3c = -4 \n" ); document.write( "0+7b-10c = 12 \n" ); document.write( "0+ 0-1c = -3 \n" ); document.write( "----------------- \n" ); document.write( "Solve for c and substitute into 1st and 2nd. \n" ); document.write( "c = 3 \n" ); document.write( "--- \n" ); document.write( "a-2b+9=-4 \n" ); document.write( "0+7b-30=12 \n" ); document.write( "--- \n" ); document.write( "Solve for b and substitute into 1st \n" ); document.write( "7b = 42 \n" ); document.write( "b = 6 \n" ); document.write( "---- \n" ); document.write( "a-2*6+9 = -4 \n" ); document.write( "a - 3 = -4 \n" ); document.write( "a = -1 \n" ); document.write( "------------------ \n" ); document.write( "Ans: \n" ); document.write( "a = -1 \n" ); document.write( "b = 6 \n" ); document.write( "c = 3 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |