document.write( "Question 181548: how can i get resolve this by gaussian elemination with back-substitution or gauss-jordan elimination?\r
\n" ); document.write( "\n" ); document.write( "3a+b-c=0
\n" ); document.write( "2a+3b-5c=1
\n" ); document.write( "a-2b+3c=-4
\n" ); document.write( "

Algebra.Com's Answer #136266 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3a +b -c= 0
\n" ); document.write( "2a+3b-5c= 1
\n" ); document.write( "a-2b+3c= -4
\n" ); document.write( "---------------
\n" ); document.write( "Rearrange the equations:
\n" ); document.write( "a-2b+3c =-4
\n" ); document.write( "3a+b-c = 0
\n" ); document.write( "2a+3b-5c= 1
\n" ); document.write( "---------------
\n" ); document.write( "Subtract 3 times the 1st from the 2nd.
\n" ); document.write( "Subtract 2times the 1st from the 3rd.
\n" ); document.write( "a-2b+3c = -4
\n" ); document.write( "0+7b-10c = 12
\n" ); document.write( "0+7b-11c = 9
\n" ); document.write( "----------------------
\n" ); document.write( "Subtract the 2nd from the 3rd.
\n" ); document.write( "a-2b+3c = -4
\n" ); document.write( "0+7b-10c = 12
\n" ); document.write( "0+ 0-1c = -3
\n" ); document.write( "-----------------
\n" ); document.write( "Solve for c and substitute into 1st and 2nd.
\n" ); document.write( "c = 3
\n" ); document.write( "---
\n" ); document.write( "a-2b+9=-4
\n" ); document.write( "0+7b-30=12
\n" ); document.write( "---
\n" ); document.write( "Solve for b and substitute into 1st
\n" ); document.write( "7b = 42
\n" ); document.write( "b = 6
\n" ); document.write( "----
\n" ); document.write( "a-2*6+9 = -4
\n" ); document.write( "a - 3 = -4
\n" ); document.write( "a = -1
\n" ); document.write( "------------------
\n" ); document.write( "Ans:
\n" ); document.write( "a = -1
\n" ); document.write( "b = 6
\n" ); document.write( "c = 3
\n" ); document.write( "========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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