document.write( "Question 181628: Helen took the bus on her way to school and ran the rest of the way. She ran 3 mins. longer than she rode. If it took her 15 mins. to arrive in school, how long was her bus ride?
\n" ); document.write( " i tried to solve the problem, I want to know if this is right pLease I need your Help::\r
\n" ); document.write( "\n" ); document.write( "EQ: x + x + 3 = 15
\n" ); document.write( " 2x + 3 = 15
\n" ); document.write( " 2x = 15 - 3
\n" ); document.write( " 2x/2 = 12/2
\n" ); document.write( " x= 6 minutes\r
\n" ); document.write( "\n" ); document.write( "Is this right?? \n" ); document.write( "

Algebra.Com's Answer #136253 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
YES!!!!! YOU ARE RIGHT ON!!! GOOD WORK!!!\r
\n" ); document.write( "\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/t
\n" ); document.write( "Let t=amount of time that she rode
\n" ); document.write( "Then t+3=amount of time that she ran
\n" ); document.write( "Now we are told that:
\n" ); document.write( "Time spent riding + time spent running=15 min, so:
\n" ); document.write( "t+t+3=15 subtract 3 from each side
\n" ); document.write( "t+t=12
\n" ); document.write( "2t=12
\n" ); document.write( "t=6 min
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
\n" ); document.write( " \n" ); document.write( "

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